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c#处理3种json数据的实例

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行业动态
2025-03-19
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“

csharp，using Newtonsoft.Json;，using System;class Program，{， static void Main()， {， string json1 = "{"Name":"John", "Age":30}";， var person = JsonConvert.DeserializeObject(json1);， Console.WriteLine($"Name: {person.Name}, Age: {person.Age}"); string json2 = "[{"Name":"Jane", "Age":25}, {"Name":"Doe", "Age":22}]";， var people = JsonConvert.DeserializeObject(json2);， foreach (var p in people)， Console.WriteLine($"Name: {p.Name}, Age: {p.Age}"); string json3 = "{"Employees":[{"Name":"Alice", "Age":32}, {"Name":"Bob", "Age":40}]}";， var employees = JsonConvert.DeserializeObject(json3);， foreach (var e in employees.Employees)， Console.WriteLine($"Name: {e.Name}, Age: {e.Age}");， }，}public class Person，{， public string Name { get; set; }， public int Age { get; set; }，}public class RootObject，{， public Person[] Employees { get; set; }，}，

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在C#中处理JSON数据通常使用Newtonsoft.Json库，它提供了方便的方法来序列化和反序列化JSON，以下是处理三种不同类型JSON数据的实例：

简单对象

假设我们有以下简单的JSON数据，表示一个用户的信息：

{
  "name": "John Doe",
  "age": 30,
  "email": "john.doe@example.com"
}

我们需要定义一个与JSON结构相对应的类：

public class User
{
    public string Name { get; set; }
    public int Age { get; set; }
    public string Email { get; set; }
}

我们可以使用JsonConvert.DeserializeObject方法将JSON字符串转换为User对象：

string json = @"{
  ""name"": ""John Doe"",
  ""age"": 30,
  ""email"": ""john.doe@example.com""
}";
User user = JsonConvert.DeserializeObject<User>(json);
Console.WriteLine($"Name: {user.Name}, Age: {user.Age}, Email: {user.Email}");

数组/列表

考虑一个包含多个用户信息的JSON数组：

c#处理3种json数据的实例

[
  {
    "name": "John Doe",
    "age": 30,
    "email": "john.doe@example.com"
  },
  {
    "name": "Jane Smith",
    "age": 25,
    "email": "jane.smith@example.com"
  }
]

我们同样定义一个User类，然后使用JsonConvert.DeserializeObject方法将JSON数组转换为User对象的列表：

string jsonArray = @"[
  {
    ""name"": ""John Doe"",
    ""age"": 30,
    ""email"": ""john.doe@example.com""
  },
  {
    ""name"": ""Jane Smith"",
    ""age"": 25,
    ""email"": ""jane.smith@example.com""
  }
]";
List<User> users = JsonConvert.DeserializeObject<List<User>>(jsonArray);
foreach (var user in users)
{
    Console.WriteLine($"Name: {user.Name}, Age: {user.Age}, Email: {user.Email}");
}

嵌套对象

考虑一个更复杂的JSON结构，其中包含嵌套对象：

{
  "user": {
    "name": "John Doe",
    "age": 30,
    "email": "john.doe@example.com"
  },
  "address": {
    "street": "123 Main St",
    "city": "Anytown",
    "zipcode": "12345"
  }
}

我们需要定义两个类，一个用于用户信息，另一个用于地址信息：

c#处理3种json数据的实例

public class Address
{
    public string Street { get; set; }
    public string City { get; set; }
    public string Zipcode { get; set; }
}
public class UserWithAddress
{
    public User User { get; set; }
    public Address Address { get; set; }
}

我们可以将JSON字符串反序列化为UserWithAddress对象：

string nestedJson = @"{
  ""user"": {
    ""name"": ""John Doe"",
    ""age"": 30,
    ""email"": ""john.doe@example.com""
  },
  ""address"": {
    ""street"": ""123 Main St"",
    ""city"": ""Anytown"",
    ""zipcode"": ""12345""
  }
}";
UserWithAddress userWithAddress = JsonConvert.DeserializeObject<UserWithAddress>(nestedJson);
Console.WriteLine($"Name: {userWithAddress.User.Name}, Age: {userWithAddress.User.Age}, Email: {userWithAddress.User.Email}");
Console.WriteLine($"Street: {userWithAddress.Address.Street}, City: {userWithAddress.Address.City}, Zipcode: {userWithAddress.Address.Zipcode}");